# Line slope calculator 2x-5y=-32

**Straight line given by points A[4; 8] and B[9; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+6.4

**Canonical form of the line equation:**2x-5y+32 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 2t+8 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -16

**Y intercept:**y

_{0}= q = 6.4

**Distance line from the origin:**d

_{0}= 5.9423

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[6.5; 9]

**Perpendicular Bisector equation:**5x+2y-50.5 = 0

**Vector OA = (4; 8) ; |OA| = 8.9443**

**Vector OB = (9; 10) ; |OB| = 13.4536**

**Scalar product OA .OB = 116**

**Angle ∠ AOB = 15°25'20″ = 0.2692 rad**