Hard Light Productions Forums
Off-Topic Discussion => General Discussion => Topic started by: Hudzy on September 22, 2002, 12:37:14 pm
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Anyone here good at maths?
What would be the reciprocal of...
u + v
v
and also...
/a\ -1
\b/
ok, that last dodgy looking thing is a over b in brackets and the -1 bit is meaning the whole thing to the power of -1. I almost confused myself there.
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v / (u+v) and a/b; just flip them over. :D
Alright, let's keep this one open; it could become a useful thread.
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What about to the power of minus 1 bit? Doesn't that change it in some mysterious way?
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/b / a\+1 ?
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Our resident physics b1tch, PJ, sez:
v/(u+v)
1/[(a/b)-1] = a/b
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What about to the power of minus 1 bit? Doesn't that change it in some mysterious way?
That means the reciprocal of the expression, so the reciprocal of a reciprocal is the same thing again.
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Hmmm... oh goody a math thread :D
Hey CP, are there any calculus/trigonometry texts that you'd recommend?
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I used one called Calculus with Analytic Geomtery (5th ed., author: Howard Anton, publisher: Wiley & sons) which I thought was a very well written text. At some 1200 pages it is quite long, but it covers not only normal first-year calculus, but all of multivariable calculus as well.
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Hmmm *me notes*
hopefully they have a copy at the university book store.... :)
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:wtf: ...
Use the formula
1 = 1 + 1
R R1 R2
(That's all missalligned. When R1 and R2 are mentioned the 1 and the 2 are small ones to the bottom right of the letter)
to find R when R1 = 20 and R2 = 25.
And yes I have left this maths homework to the last minute. :nervous:
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100/9 :p
Hmmm *me notes*
hopefully they have a copy at the university book store.... :)
The edition I have is an older one, but there are many universities using newer versions, so it should be pretty easy to find.
I really want this one but look at that price! ridiculous... :mad:
http://www.amazon.com/exec/obidos/tg/detail/-/2881248640/qid=1032725333/sr=1-7/ref=sr_1_7/102-6697478-5305726?v=glance&s=books
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Ok, how did you work that out? :confused: I might as well learn something. :D
Actually, I can see how that's done now. It must be getting late. :nod:
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1/R=1/20 + 1/25
1
- = .09
R
.09R=1
9R=100
R=100/9
This is easy stuff man, CP needs some problems that takes days to do :p
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I think I'd rather speak politics. :doubt:
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Originally posted by RKIF-DragonClaw
This is easy stuff man, CP needs some problems that takes days to do :p
Yeah, I know. I'm just panicing at the moment and it's late and I suck at maths. Combine the three and well.
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raaaaaaghaahaaaaaaaaaaaaaaaaagrrrrrrraaaaaaaaaaa !!
*Nukes him self*
Ooooh...look at the prety light.
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Originally posted by Hudzy
Anyone here good at maths?
What would be the reciprocal of...
u + v
v
Be this physics?
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Maths. Number and algebra to be more precise.
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Wheeeeeee! A homework thread!
My math prof regularly leaves class to buy an ice cream bar then returns and eats it while teaching.
Oh, and for lining things up use the Code tag. Like so:
1 = 1 + 1
- -- --
R R1 R2
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If a car is going 70 k/m and is 100 meters from a stop sign, and is decelerating at 4 m/s/s. Is it able to stop within 100 meters?
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lemme check
*hops in car*
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well ok.. i actually did the math. it's either : The car stops in 6 seconds , 76 meters away, so yes. or it's no :) i messed up the "no" so thats why i think the first one.
CP, back me up :)
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Originally posted by CODEDOG ND
If a car is going 70 k/m and is 100 meters from a stop sign, and is decelerating at 4 m/s/s. Is it able to stop within 100 meters?
whats the mass of the car, force of friction between the tires and the pavement, and why is it in k/m?
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why is it in k/m?
because he had to track bambi to Europe/Canada, and couldn't do his Math homework because his excuse was "I only know the metric system now" ... i don't need don't explain his techers response ;)
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If a car is going 70 k/m and is 100 meters from a stop sign, and is decelerating at 4 m/s/s. Is it able to stop within 100 meters?
I'm not sure of the units for the velocity but it looks like it might be km/min. That's one heck of a fast car though. :wtf: Anyway, it is not going to be able to stop seeing as it is going at an incredible speed. (almost 2600mph) Perhaps you meant something else for the speed?
This is actually a physics question, but those are pretty nice too. :D
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CP, check that again.. 70 Kilometers an hour.. that's like 40 something miles an hour i think..
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Is it per hour? I thought it was per minute... :p
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:lol: :lol: :lol:
Am i right then, if its per hour?
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Well, I will assume for the moment that it is km/h and that there are no retarding forces due to friction or air resistance. This stuff can just be plugged into one of the usual kinematics equations for constant acceleration:
v1²=v0²+2ax
x=30625/648=47.2608
I think it should be able to stop before getting halfway there. Might have messed up there though; been doing too much pure math lately. :p
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stop before getting half way there as in 76 meteres away?
I made a nice lil' chart, i could show it to you in Excel form if you like?