Hard Light Productions Forums
Off-Topic Discussion => General Discussion => Topic started by: Ghostavo on January 17, 2005, 06:22:55 pm
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A few days ago I was given this problem and I am unable to find a solution. You are given the following sum:
1¹+2²+3³+(...)+2003²°°³+2004^2004+2005^2005
To which you must find the unit's digit, all of this with just a piece of paper, a pencil and your head.
:sigh:
Help?
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You do the thing where you take the first 5 numbers on top, then the next 5 and add them I believe so it's something like
1^1, 2^2, 3^3
2005^2005
Im sure someone else knows how to do it but thats the way i would think it would be done.(if you understand what I am saying)
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So basically...
2005
(http://www.bized.ac.uk/timeweb/images/sigma.gif)r^r
r=1
I probably should know how to do this.
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Corsair, how big is that piece of paper?:p
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ok so if you were paddling your canoe down mainstreet and all four tires fell off how many pancakes does it take to make a doghouse?
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Pi minus a Bm7.
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Originally posted by Mr. Vega
Corsair, how big is that piece of paper?:p
Small handwriting. :p
Hey Solatar, what's a Bm7?
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Correct me if I'm wrong, but isn't this just a case of using that stupid geometric progression formula thingy?
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that problem made my TI89 cry :(
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Originally posted by Corsair
Hey Solatar, what's a Bm7?
B minor 7th, it's a music chord.
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adwight, could you be more specific? I can't understand what you mean.
Corsair, this was to be done in less than 2 hours (this was part of a 4 exercise "test"). Yeah that's it, but after reaching there the whole thing goes to hell, if I had about 1 or 2 days I'd probably do it the hard way (calculate it all) but this was not the case as I said before.
an0n, explain?
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If I could 'explain', I'd've tried to apply my theory to the problem by now.
All I've got is a vague memory of some quick way to figure out geometric progressions (assuming that's what this is).
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But this is not geometric, it's exponencial...
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I came up with this right after Ghostavo left #nodewar:
< Joey_21 > 1, 4, 7, 6, 5, 6, 3, 6, 9, 0, 1, 6, 3, 6, 5, 6, 7, 4, 9, 0
< Joey_21 > next digits: 1, 4, 7, 6, 5, 6, 3, 6, 9, 0...
< Joey_21 > 1^1 ends in 1, 2^2 ends in 4, 3^3 ends in 7, 4^4 ends in 6.... 20^20 ends in a 0, there the pattern starts repeating
< Joey_21 > 2000^2000 ends in 0, 2001^2001 ends in 1, 2002^2002 ends in 4, 2003^2003 ends in 7, 2004^2004 ends in 6, 2005^2005 ends in 5
< Joey_21 > there we see the sequence 0, 1, 4, 7, 6, 5 again
I don't have the time to continue it from here because I have to go to class in a few minutes. Good luck!
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Originally posted by Solatar
B minor 7th, it's a music chord.
D'oh. I knew that. I thought you meant something in math, not music. ;)
an0n, like Ghostavo said, it isn't geometric so you can't use those formulas because they don't describe the increasing exponent.