Author Topic: Help with maths  (Read 1432 times)

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Offline Dark RevenantX

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Offline Wanderer

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Quote
Originally posted by Ashrak
in the end of the second one why do you substitute x as 1 instead of infinity?


Sorry for this coming so late but i really thought you knew (as you seem to know at least the basics of the limits) that you can not divide infinite by infinite (or zero by zero) unless you know the tricks to make it work, like classic lim(x->0) sin x / x (it is "0/0" case) which equals 1. You can not have the infinate existing in both numerator and the denominator as you can not divide undefined value by another undefined value (as infinite is by defination an undefined value).

So in the calculation i simply builded the fraction or in other words multiplied both the numerator and the denominator by the same value, in this case the value was Sqr(1/x) (i hope these are the English terms). So i got following: Sqr(x)Sqr(1/x) =Sqr(x/x) =Sqr(1) =1 and Sqr(x+1)Sqr(1/x) =Sqr(x/x+1/x) =Sqr(1+1/x).
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