Arrived in slightly different special function, maybe someone could explain why?
And how the hell you can put up those neato integrate signs here?
Integrate:
ln(tan x) dx || Substituted tan(x)=u and solved dx = 1/(1+u^2) du
Arrived at:
INT { ln(u)*[1/(1+u^2)] }du, partial integration resulted in
ln(u)*arctan(u) - INT { arctan(u)/u }du, which results in a special function also.
The handbook of mathematical functions, (Abramowitz-Stegun) states that:
INT { arctan(u) / u } du = INT from 0 to INF { exp(-u*t)*si(t) }dt,
where si is a special function also, defined on the same book.
It was probably something like INT from Z to INF { (sin t) / t }dt.
Mika