Author Topic: Spaceship two unveiled  (Read 5036 times)

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Offline Thaeris

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I believe most of that is correct, however lift characteristics are also closely tied to the physical geometry of the airfoil itself. If you're dealing with a symmetrical cross-section airfoil, ideally you should not be generating any lift in direct forward flight. With a cambered airfoil, the foil itself has a sort of AoA already inherent in the foil itself, meaning that in forward flight, zero AoA, the foil will generate lift when accelerated/propelled through the air.

With extreme speeds and extreme altitudes, this is what I see happening with a symmetrical, neutral lift at zero AoA foil (on a spaceplane, of course):

Given such velocity (also aided by the fact that low atmospheric density provides little resistance for the craft in question, aiding in high speed flight) and such altitude, the craft, despite being at 0 AoA in relation to the planet, will climb as its rotational velocity/acceleration (in relation to Earth) is such that it pulls away from the downward force of gravity whose origin (in this case) of course is the planet.

I can't say truthfully that this is indeed the case, but I'm pretty sure it's a valid argument. Thus, to continue accelerating in a line (which is actually an arc - it is a planet, after all...), you'd need to have a negative AoA. This would be even more apparent in an aircraft with a cambered airfoil...
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Offline watsisname

As an aside, if your craft is within the atmosphere but has a velocity which is a large fraction of orbital velocity, then the amount of lift needed to remain at a given altitude will be less.  This is because the vertical acceleration of your trajectory is much less.  With a good lift/drag ratio, a craft can coast, unpowered, through the upper atmosphere at suborbital speed for a very long time.
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Offline Nuke

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also some aircraft designs angled their wings angled in relation to the longitudinal axis. so that they have a slightly higher than normal aoa in level flight. neutral airfoils in this position would still produce some lift (.11 per degree). actual airfoil geometry is mostly represented in the Cl. when it comes right down to it, the only way to figure out what the Cl of an airfoil is, is to put it in a wind tunnel and test it.
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