Originally posted by Razor
First, he is not confusing me. I (think I) know exactly what he is talking about.
It may be linear algebra. The chapter name is: Curves and vector functions. There is also something called: "Polar" coordinates and about finding something called: cartesis (sp) coordinates. Some guy called: Rene Descartes invented those. But what is really confusing to me is something called: areas and polar coordinates. It is something about calculating areal coverage of a graph (which is usually a curve line or a spiral created with a particular function) by using Integral functions.
By the way, this is funny stuff. Some of those lines can look like flowers or something. 
There is also something about parameters and stuff. By the way CP, do you have any clue what I am talking about? It's tough to translate stuff from Norwegian to English.
Cartesian Co-ordinates are the ones you are used to (three values from a given point in the x, y and z directions), Polar co-ordinates (in 2D anyways) is where you have an angle from a line and a direction from a pole (hence the name), there are also parametric co-ordinates. I think the course wants you to be able to find the cartesian equation (thing you're used to finging ie. x=y=z) from vector equations.
Here's some formulas for areas 3D shapes
|axb|.c = for a parallelapiped (sp?)
1/6 |axb|.c = for a tetrahedron
|a|^3 = for a cube
1/2|axb|*c = for a triangular prisim
|a|*|b|*|c| = for a cuboid
a, b and c are the vectors which make up your shape
a= (a1,a2,a3) b = (b1,b2,b3) c = (c1,c2,c3)
* means multiply
|| means the lenglth of the vector (use pythagaros for single ones)
x means the vector product. It can be found by putting your vectors a and b into the 2nd and third row of a 3by3 matrix and then finding the determinant. eg ([x,y,z],[a1,a2,a3],[b1,b2,b3]). If you don't know how do do that then find out, the alternative method is bloody long.
. is the scalar product, multiply each dimention together then add them up eg a.b = (a1*b1)+(a2*b2)+(a3*b3)
I doubt you'll be given curves in vector form so you should be OK.
