So about how much thrust could something like that (or any of the other suggestioned designs) make?
Oh brother...
I'm gonna mostly ignore the neutron flux, because I assume you don't have a way to redirect them neutrons towards the rear of your ship - an easy task with alpha particles because of their +2e charge (damn, this starts to sound like an RPG

), all it takes is a magnetic field... neutral particles won't change their direction in mag field, so the neutrinos from the reaction would travel on pretty much linear trajectories, and assuming your fusion chamber is still mostly concealed by the ship, the ship's structure would be equally or almost equally hit by them -> no notable change of momentum from them.
Okay then... Assuming you're using deuterium-tritium fusion fuel mix, the resulting helium nuclei (alpha particles) will have roughly 3.5 MeV energy (
source, about what kind of nuclei were observed coming from fusion going on in JET tokamak reactor running a 1.5 MW fusion reaction).
3.5 MeV is 5.60761762e10^-13 Joules of kinetic energy on each helium nuclei produced. From this it's easy to calculate the velocity of the nuclei - that is
E(k) = ½ m v^2
v^2 = 2 E(k) / m
v = Sqrt (2 E(k) / m)
since the mass of alpha particle is 6.644656e10^-27 kg, just throw them into the equation to see that the velocity is
v =~12991758.6 m/s, which is a heck of a lot of speed. Just to check if it's accurate, compare it to speed of light - approximately 300,000,000 m/s. The velocity of the alpha nuclei seems to be about 4% of speed of light, which is thankful because now it's unnecessary to use relativistic equations for defining momentums and stuff - for the accuracy we require, anyway.
Okay, now we have the (average) velocity of alpha nuclei, and we're going to divert their vector towards the rear of the ship, so that effectively the ship gains the same momentum as each alpha nuclei, but forwards.
Now the momentum of a single alpha nuclei seems to be about
p = m*v =~ 8.633e-20 kgm/s
And every reaction releases one of these critters. Okay then, using chemistry terms, if we have one mole of deuterium nuclei (not molecules!) and one mole of tritium nuclei, we end up with one mole of helium nuclei, assuming the fusion is perfect (which isn't gonna happen but since we're looking for upper limits, best case scenario, it's OK).
Deuterium's atomic weight is 2u, tritium's is 3u, helium's is 4u (and the neutron that goes away is 1u, but nevermind that now). Roughly. There are some mass loss, but on this scale, it's not all that notable anyway, so I'm gonna blatantly ignore it aside from saying that actually helium+neutron weighs a little less than deuterium+tritium, and that's it. Helpfully, the atomic mass unit is configured so that when the atomic weight is 1 u, one mole contains one gram of the matter.
So, when the engine consumes grand total of 5 grams of deuterium-tritium mix (in proper ratios), it gives us 4 grams of helium to use as propellant.
Now then... the one mole of helium weighs (about) 4 grams, as was determined. One mole contains 6.0221415e23 particles (Avogadro's number), which means we're gonna multiply the momentum with this... multiplier number... to determine the momentum that the ship can at best gain from using grand total of 5 grams of fusion fuel:
p = 6.0221415e23 * 8.633e-20 kgm/s = 51989.1475695 kgm/s
which
feels like a lot of momentum, but what it essentially means is that with 5 grams of fuel, you will manage to make a 52 ton ship travel at a whopping one metre per second, in the time it takes for the reactor to consume the 5 grams of detrimix fuel...
To put it in thrust terms (or force);
F = dp/dt
which means that if the fusion reactor can consume 5 grams of fuel in, say, 60 seconds, the thrust from it would be
F = 52000 kgm/s / 60 s = 866.7 N
If the reactor can use the mentioned 5 grams of fuel in 1 second, the maximum thrust would be 52 kN.
And seeing how utterly incredible amounts of energy are released, the achieved momentum/thrust/acceleration ratio is not really mind-bogglingly good. Also when you think of 52 ton space ship, you should be looking at something about the size of a good-sized airliner (like Airbus A320, or perhaps Boeing 757) as a reference to size, and compare to existing chemical rocket engines - Apollo-type service module engine produced 98kN thrust.
And I reserve the very viable possibility that something went wrong in the calculations.
As a final analysis, it's obvious that as far as propellant consumption is considered, this kind of drive is rather efficient, but propellant consumption is not all in all. In this case, fusionable isotopes are not as abundant as normal hydrogen in space, so where you gonna get all those precious grams of detrimix fuel?