# Line slope calculator 8x+5y=40

**Straight line given by points A[0; 8] and B[5; 0]**

## Calculation:

**Slope-intercept form of line:**y = -1.6x+8

**Canonical form of the line equation:**8x+5y-40 = 0

**Parametric form of the line equation:**

x = 5t

y = -8t+8 ; t ∈ R

**Slope:**m = -1.6

**Slope angle of line: φ =**-57°59'41″ = -1.0122 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 4.24

**The length of the segment AB: |AB| =**9.434

**Vector: AB =**(5; -8)

**Normal vector: n =**(8; 5)

**Midpoint of the segment AB: M =**[2.5; 4]

**Perpendicular Bisector equation:**5x-8y+19.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (5; 0) ; |OB| = 5**

**Scalar product OA .OB = 0**

**Angle ∠ AOB = 90° = 1.5708 rad**