I made some oversimplifications.
Lower limit of Collie speed (minimum energy transfer into kinetic energy):
m(R)*v1(R) = m(C)*v + m(R)*v
v1(R) = (m(C)/m(R)+1) *v
v= 15m/s*1/(6+1) = ~ 2,14 m/s for both the Collie and the Repulse after Collision.
Upper limit (maximum energy transfer into kinetic energy):
0,5 m(R)*v1(R)² = 0,5 m(R)*v2(R)² + 0,5 m(C)*v(C)² (ignoring momentum)
m(R)/m(C) * v1(R)² = v(C)²
(1/sqrt(6)) *15m/s = v(C) = ~6,12m/s
If you factor in momentum, this limit will be further reduced.
The conservation of momentum only applies if no force is applied.
If no
outside force is applied. There is no outside force, that's why it's a closed system. => conservation of momentum applies
[edit]
Maybe look at Newton's third law of motion.
http://en.wikipedia.org/wiki/Newton%27s_laws_of_motionTo clarify: If no energy is absorbed, we will have a completely elastic collision, like two rubber balls bouncing off of each other.